Chapter 19
Ionic Equilibria in Aqueous Systems
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The effect of addition of acid or base to an unbuffered solution
base added
acid added
The effect of addition of acid or base to a buffered solution
acid added
base added
2
An acid-base buffer is a solution that lessens the impact on pH from the addition of acid or base.
Most often, the components of a buffer are the conjugate acid-base pair of a weak acid (or base).
Buffers work through a phenomenon known as the common-ion effect .
CH 3 COOH( aq ) + H 2 O( l ) H 3 O + ( aq ) + CH 3 COO - ( aq )
If some CH 3 COO - ion is added, the equilibrium position shifts to the left; thus, [H 3 O + ] decreases, lowering the extent of acid dissociation.
Similarly, if acetic acid is dissolved in a sodium acetate solution, acetate ion and H 3 O + ion from the acid enter the solution. The acetate ion already present in the solution prevents the acid from dissociating as much as it would in pure water, thus lowering [H 3 O + ].
In this case, acetate ion is called the common ion .
The common-ion effect occurs when a given ion is added to an equilibrium mixture that already contains that ion, and the position of the equilibrium shifts away from forming more of it.
2
How a buffer works
2
The Henderson-Hasselbalch Equation
2 3 + -
3 + -
K a
3 + K a
-
-
3 + K a
[base]
pH = p K a + log
[acid]
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Buffer Capacity and Buffer Range
Buffer capacity is the ability to resist pH change
A buffer has the highest capacity when the component concentrations are equal (in other terms, its pH ≈ p K a of its acid component)
Buffer range is the pH range over which the buffer acts effectively
Buffers have a usable range within ± 1 pH unit of the p K a of its acid component.
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The relation between buffer capacity and pH change
6
Colors and approximate pH range of some common acid-base indicators
An acid-base indicator is a weak acid, with a different color than its conjugate base and with the color change occuring over a specific and narrow pH range.
6
The color change of the indicator bromthymol blue
Basic
Acidic
6
6
Curve for a weak acid-strong base titration.
6
Sample Problem 19.4
Calculate the pH during the titration of 40.00 mL of 0.1000 M propanoic acid (HPr; K a = 1.3 x 10 -5 ) after adding the following volumes of 0.1000 M NaOH:
(a) 0.00 mL
(b) 30.00 mL
(c) 40.00 mL
(d) 50.00 mL
The amounts of HPr and Pr - will be changing during the titration. Remember to adjust the total volume of solution after each addition.
Find the starting pH using the methods of Sample Problem 18.8.
[Pr - ][H 3 O + ]
[Pr - ] = x = [H 3 O + ]
K a =
[HPr]
x = 1.1 x 10 -3 ; pH = 2.96
HPr( aq ) + OH - ( aq ) Pr - ( aq ) + H 2 O ( l )
-
0.004000
0
-
Initial
0.003000
-
Change
-
-
Final
0
-
0.001000
0.003000
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Sample Problem 19.4
continued (2 of 3)
0.001000 mol
[H 3 O + ] = 1.3 x 10 -5 x
= 4.3 x 10 -6 M
pH = 5.37
0.003000 mol
(c) When 40.00 mL of NaOH are added, all of the HPr will be reacted and the [Pr - ] will be
(0.004000 mol)
= 0.05000 M
(0.004000 L) + (0.004000 L)
1.0 x 10 -14
K w
K a x K b = K w
K b = = = 7.7 x 10 -10
1.3 x 10 -5
K a
K w
[H 3 O + ] = = 1.6 x 10 -9 M
pH = 8.80
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Sample Problem 19.4
continued (3 of 3)
(d) 50.00 mL of NaOH will produce an excess of OH - .
mol excess base = (0.1000 M )(0.05000 L - 0.04000 L) = 0.00100 mol
1.0 x 10 -14
M = (0.00100 mol)
M = 0.01111
[H 3 O + ] = = 9.0 x 10 -13 M
(0.0900 L)
0.01111
pH = 12.05
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Curve for a weak base-strong acid titration
15
Formation of acidic precipitation
15